[Fwd: Re: formula for trans/recv settings]

Mark L. Bardenwerper (bardenwe@vbe.com)
Mon, 26 May 1997 18:37:01 -0500


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Bill has a better handle on the formula I sent to the list and to Ron
Riggi <rriggi@theriver.com>:

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Received: from zoom.bga.com by serv1.vbe.com via ESMTP (950413.SGI.8.6.12/940406.SGI.AUTO) for <bardenwe@vbe.com> id SAA14002; Mon, 26 May 1997 18:19:39 -0500 Received: from squeek.tdoc.texas.gov ([204.64.172.2]) by zoom.bga.com (8.6.12/8.6.12) with SMTP id SAA06546 for <bardenwe@vbe.com>; Mon, 26 May 1997 18:23:51 -0500 Message-Id: <3.0.32.19970526182439.006bf92c@bga.com> X-Sender: wcw@bga.com X-Mailer: Windows Eudora Pro Version 3.0 (32) Date: Mon, 26 May 1997 18:24:43 -0500 To: bardenwe From: Bill Woodland <wcw@bga.com> Subject: Re: formula for trans/recv settings Mime-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

At 05:13 PM 5/26/97 -0500, you wrote: >you have a 33,6 modem, you are restricted to roughly 33. So, you should >set your transmit to 12. OK: 33-12=3D21. Set your recieve to 20 or 21. You

Mark:

I agree that this doesn't work so well with CU, as for some reason my chat gets lost if I try to send higher than about 18k, but just keep in mind that modems are full duplex...you can send at 28k and receive at 28k both at the same time. This formula of yours would be fine if they were half duplex. I usually set my transmit to 18, and my receive to 24 or 26, because my modem usually connects at 24000 or 26400. =20

18+24=3D42, 18+26=3D44, but it's a 28.8 modem.

Bill Woodland (Squeek =A9) PC questions only, please. URL:http://cu-seeme.cornell.edu/~WCW CU-seeME Unsubscribe? Details at http://cu-seeme.cornell.edu/listinfo.html

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